Integrand size = 22, antiderivative size = 90 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=-\frac {b (b c-a d) x^2}{d^3}+\frac {b^2 x^4}{4 d^2}+\frac {c (b c-a d)^2}{2 d^4 \left (c+d x^2\right )}+\frac {(b c-a d) (3 b c-a d) \log \left (c+d x^2\right )}{2 d^4} \]
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Time = 0.08 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {457, 78} \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {c (b c-a d)^2}{2 d^4 \left (c+d x^2\right )}+\frac {(b c-a d) (3 b c-a d) \log \left (c+d x^2\right )}{2 d^4}-\frac {b x^2 (b c-a d)}{d^3}+\frac {b^2 x^4}{4 d^2} \]
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Rule 78
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x (a+b x)^2}{(c+d x)^2} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (-\frac {2 b (b c-a d)}{d^3}+\frac {b^2 x}{d^2}-\frac {c (b c-a d)^2}{d^3 (c+d x)^2}+\frac {(b c-a d) (3 b c-a d)}{d^3 (c+d x)}\right ) \, dx,x,x^2\right ) \\ & = -\frac {b (b c-a d) x^2}{d^3}+\frac {b^2 x^4}{4 d^2}+\frac {c (b c-a d)^2}{2 d^4 \left (c+d x^2\right )}+\frac {(b c-a d) (3 b c-a d) \log \left (c+d x^2\right )}{2 d^4} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.97 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {4 b d (-b c+a d) x^2+b^2 d^2 x^4+\frac {2 c (b c-a d)^2}{c+d x^2}+2 \left (3 b^2 c^2-4 a b c d+a^2 d^2\right ) \log \left (c+d x^2\right )}{4 d^4} \]
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Time = 2.76 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.89
method | result | size |
default | \(\frac {\left (b d \,x^{2}+2 a d -2 b c \right )^{2}}{4 d^{4}}+\frac {\left (a d -b c \right ) \left (\frac {\left (a d -3 b c \right ) \ln \left (d \,x^{2}+c \right )}{d}+\frac {\left (a d -b c \right ) c}{d \left (d \,x^{2}+c \right )}\right )}{2 d^{3}}\) | \(80\) |
norman | \(\frac {\frac {b^{2} x^{6}}{4 d}+\frac {b \left (4 a d -3 b c \right ) x^{4}}{4 d^{2}}-\frac {\left (c \,a^{2} d^{2}-4 a b \,c^{2} d +3 b^{2} c^{3}\right ) x^{2}}{2 d^{3} c}}{d \,x^{2}+c}+\frac {\left (a^{2} d^{2}-4 a b c d +3 b^{2} c^{2}\right ) \ln \left (d \,x^{2}+c \right )}{2 d^{4}}\) | \(113\) |
risch | \(\frac {b^{2} x^{4}}{4 d^{2}}+\frac {x^{2} a b}{d^{2}}-\frac {x^{2} b^{2} c}{d^{3}}+\frac {a^{2}}{d^{2}}-\frac {2 a b c}{d^{3}}+\frac {b^{2} c^{2}}{d^{4}}+\frac {c \,a^{2}}{2 d^{2} \left (d \,x^{2}+c \right )}-\frac {c^{2} a b}{d^{3} \left (d \,x^{2}+c \right )}+\frac {c^{3} b^{2}}{2 d^{4} \left (d \,x^{2}+c \right )}+\frac {\ln \left (d \,x^{2}+c \right ) a^{2}}{2 d^{2}}-\frac {2 \ln \left (d \,x^{2}+c \right ) a b c}{d^{3}}+\frac {3 \ln \left (d \,x^{2}+c \right ) b^{2} c^{2}}{2 d^{4}}\) | \(167\) |
parallelrisch | \(\frac {b^{2} d^{3} x^{6}+4 x^{4} a b \,d^{3}-3 x^{4} b^{2} c \,d^{2}+2 \ln \left (d \,x^{2}+c \right ) x^{2} a^{2} d^{3}-8 \ln \left (d \,x^{2}+c \right ) x^{2} a b c \,d^{2}+6 \ln \left (d \,x^{2}+c \right ) x^{2} b^{2} c^{2} d +2 \ln \left (d \,x^{2}+c \right ) a^{2} c \,d^{2}-8 \ln \left (d \,x^{2}+c \right ) a b \,c^{2} d +6 \ln \left (d \,x^{2}+c \right ) b^{2} c^{3}+2 c \,a^{2} d^{2}-8 a b \,c^{2} d +6 b^{2} c^{3}}{4 d^{4} \left (d \,x^{2}+c \right )}\) | \(180\) |
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Time = 0.25 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.79 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {b^{2} d^{3} x^{6} + 2 \, b^{2} c^{3} - 4 \, a b c^{2} d + 2 \, a^{2} c d^{2} - {\left (3 \, b^{2} c d^{2} - 4 \, a b d^{3}\right )} x^{4} - 4 \, {\left (b^{2} c^{2} d - a b c d^{2}\right )} x^{2} + 2 \, {\left (3 \, b^{2} c^{3} - 4 \, a b c^{2} d + a^{2} c d^{2} + {\left (3 \, b^{2} c^{2} d - 4 \, a b c d^{2} + a^{2} d^{3}\right )} x^{2}\right )} \log \left (d x^{2} + c\right )}{4 \, {\left (d^{5} x^{2} + c d^{4}\right )}} \]
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Time = 0.53 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.10 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {b^{2} x^{4}}{4 d^{2}} + x^{2} \left (\frac {a b}{d^{2}} - \frac {b^{2} c}{d^{3}}\right ) + \frac {a^{2} c d^{2} - 2 a b c^{2} d + b^{2} c^{3}}{2 c d^{4} + 2 d^{5} x^{2}} + \frac {\left (a d - 3 b c\right ) \left (a d - b c\right ) \log {\left (c + d x^{2} \right )}}{2 d^{4}} \]
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Time = 0.19 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.19 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}}{2 \, {\left (d^{5} x^{2} + c d^{4}\right )}} + \frac {b^{2} d x^{4} - 4 \, {\left (b^{2} c - a b d\right )} x^{2}}{4 \, d^{3}} + \frac {{\left (3 \, b^{2} c^{2} - 4 \, a b c d + a^{2} d^{2}\right )} \log \left (d x^{2} + c\right )}{2 \, d^{4}} \]
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Time = 0.28 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.81 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {\frac {{\left (d x^{2} + c\right )}^{2} {\left (b^{2} - \frac {2 \, {\left (3 \, b^{2} c d - 2 \, a b d^{2}\right )}}{{\left (d x^{2} + c\right )} d}\right )}}{d^{3}} - \frac {2 \, {\left (3 \, b^{2} c^{2} - 4 \, a b c d + a^{2} d^{2}\right )} \log \left (\frac {{\left | d x^{2} + c \right |}}{{\left (d x^{2} + c\right )}^{2} {\left | d \right |}}\right )}{d^{3}} + \frac {2 \, {\left (\frac {b^{2} c^{3} d^{2}}{d x^{2} + c} - \frac {2 \, a b c^{2} d^{3}}{d x^{2} + c} + \frac {a^{2} c d^{4}}{d x^{2} + c}\right )}}{d^{5}}}{4 \, d} \]
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Time = 5.07 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.24 \[ \int \frac {x^3 \left (a+b x^2\right )^2}{\left (c+d x^2\right )^2} \, dx=\frac {a^2\,c\,d^2-2\,a\,b\,c^2\,d+b^2\,c^3}{2\,d\,\left (d^4\,x^2+c\,d^3\right )}-x^2\,\left (\frac {b^2\,c}{d^3}-\frac {a\,b}{d^2}\right )+\frac {b^2\,x^4}{4\,d^2}+\frac {\ln \left (d\,x^2+c\right )\,\left (a^2\,d^2-4\,a\,b\,c\,d+3\,b^2\,c^2\right )}{2\,d^4} \]
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